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Q: A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?

  • 1
    136/345
  • 2
    17/87
  • 3
    316/435
  • 4
    158/435
  • Show Answer
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Answer : 3. "316/435"
Explanation :

Answer: C) 316/435 Explanation: ns=C230    Let A be the event of getting two oranges and     B be the event of getting two non-defective fruits.    and A∩B be the event of getting two non-defective oranges    ∴ PA=C220C230, PB=C222C230 and PA∩B=C215C230    ∴PA∪B=PA+PB-PA∩B   = C220C230+C222C230-C215C230=316435

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