Aptitude Questions Practice Question and Answer
8Q: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 890 15b5cc6f4e4d2b4197774f013
5b5cc6f4e4d2b4197774f013- 114 cmfalse
- 213.5 cmfalse
- 312.5 cmtrue
- 411.4 cmfalse
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Answer : 3. "12.5 cm"
Explanation :
Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : xтЗТ 40.25 ├Ч x = 28.75 ├Ч 17.5тЗТ x = 28.75 ├Ч 17.5/40.25= 2875 ├Ч 175/40250= 2875 ├Ч 7/1610= 2875/230= 575/46= 12.5 cm
Q: рдПрдХ рд╡реНрдпрд╛рдкрд╛рд░реА рдиреЗ 5000 рд░реВрдкрдпреЗрдВ рдкреНрд░рддрд┐ рд╡рд╕реНрддреБ рдХреА рджрд░ рд╕реЗ рджреЛ рд╡рд╕реНрддреБрдПрдБ рдмреЗрдЪ рджреАред рдПрдХ рд╡рд╕реНрддреБ рдХреЛ рд╡рд╣ 20 рдкреНрд░рддрд┐рд╢рдд рдХреА рд╣рд╛рдирд┐ рдкрд░ рддрдерд╛ рджреВрд╕рд░реА рд╡рд╕реНрддреБ рдХреЛ 20 рдкреНрд░рддрд┐рд╢рдд рдХреЗ рд▓рд╛рдн рдкрд░ рдмреЗрдЪ рджреЗрддрд╛ рд╣реИред рдкреВрд░реЗ рд╕реМрджреЗ рдореЗрдВ рдЙрд╕реЗ рдХрд┐рддрдиреЗ рдкреНрд░рддрд┐рд╢рдд рдХрд╛ рд▓рд╛рдн рдпрд╛ рд╣рд╛рдирд┐ рдХреА рдкреНрд░рд╛рдкреНрддрд┐ рд╣реБрдпреА- 3216 05d13414c40daee3c552fcb44
5d13414c40daee3c552fcb44- 14 % рд▓рд╛рднfalse
- 24% рд╣рд╛рдирд┐true
- 320% рд▓рд╛рднfalse
- 4рди рддреЛ рд▓рд╛рдн рди рд╣рд╛рдирд┐false
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Answer : 2. "4% рд╣рд╛рдирд┐"
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 2752 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, ┬а At particular time for all object , ratio of height and shadow are same. ┬а Let the height of the pole be 'H' ┬а Then ┬а188=H48 ┬а => H = 108 m.
Q: Solve the equation 122x+1┬а=┬а1┬а? 3394 05b5cc6f4e4d2b4197774efd7
5b5cc6f4e4d2b4197774efd7- 1-1/2true
- 21/2false
- 31false
- 4-1false
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Answer : 1. "-1/2"
Explanation :
Answer: A) -1/2 Explanation: Rewrite equation as┬а122x+1┬а=┬а120 ┬а Leads to 2x + 1 = 0┬а ┬а Solve for x : x = -1/2
Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 1727 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
Q: What is the number of digits in┬а333? Given that log3 = 0.47712? 4759 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: ┬аLet ┬а┬аLet┬аx=333┬а=┬а333 ┬а ┬аThen,┬аlogx┬а=┬а33┬аlog3┬а┬а ┬а = 27 x 0.47712 = 12.88224┬а ┬а Since the characteristic in the resultant value of log x is 12 ┬а тИ┤The number of digits in x is (12 + 1) = 13┬а ┬а Hence the required number of digits in┬а333is 13.
Q: рдПрдХ рджреБрдХрд╛рдирджрд╛рд░ рд░реВрдкрдпреЗ рдореЗрдВ 5 рдХреЗ рднрд╛рд╡ рд╕реЗ рдирд╛рд░рдВрдЧреА рдмреЗрдЪрд╛ рдФрд░ рдЙрд╕реЗ 20 рдкреНрд░рддрд┐рд╢рдд рдХрд╛ рд▓рд╛рдн рдкреНрд░рд╛рдкреНрдд рд╣реБрдЖред рд╡рд╣ рд░реВрдкрдпреЗ рдореЗрдВ рдХрд┐рд╕ рднрд╛рд╡ рд╕реЗ рдирд╛рдВрд░рдЧреА рдЦрд░реАрджрд╛ рдерд╛? 2517 05d1338f2d2441c3c5ff90a35
5d1338f2d2441c3c5ff90a35- 13false
- 27false
- 34false
- 46true
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Answer : 4. "6"
Q: рдПрдХ рдмрд╕ рдмрд┐рдирд╛ рдХреЛрдИ рд░реВрдХрд╛рд╡рдЯ рдХреЗ 75 рдХрд┐рдореА/рдШрдВрдЯрд╛ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдЪрд▓ рд░рд╣реА рд╣реИред рдкрд░рдиреНрддреБ рд░реВрдХрд╛рд╡рдЯ рдХреЗ рд╕рд╛рде 60 рдХрд┐рдореА/рдШрдВрдЯрд╛ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдЪрд▓ рдкрд╛рддреА рд╣реИред рдкреНрд░рддрд┐ рдШрдВрдЯрд╛ рд░реВрдХрд╛рд╡рдЯ рдХреА рджрд░ рдЬреНрдЮрд╛рдд рдХрд░реЗрдВ? 1326 05d15ed1d5fdb2c68495d9dee
5d15ed1d5fdb2c68495d9dee- 110 рдорд┐рдирдЯfalse
- 215 рдорд┐рдирдЯfalse
- 312 рдорд┐рдирдЯtrue
- 420 рдорд┐рдирдЯfalse
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