Aptitude Questions Practice Question and Answer

Q: Find value of log27 +log 8 +log1000log 120 1415 1

  • 1
    1/2
    Correct
    Wrong
  • 2
    3/2
    Correct
    Wrong
  • 3
    2
    Correct
    Wrong
  • 4
    2/3
    Correct
    Wrong
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Answer : 2. "3/2"
Explanation :

Answer: B) 3/2 Explanation:  = log 33 + log 23+ log 103log10×3×22        =log33 12+log 23+log 10312log(10×3×22)                 =12log 33+3 log 2+12 log103log10+log3+log22                 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32

Q: What is the number of digits in 333? Given that log3 = 0.47712? 4759 0

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    12
    Correct
    Wrong
  • 2
    13
    Correct
    Wrong
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    14
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 2. "13"
Explanation :

Answer: B) 13 Explanation:  Let   Let x=333 = 333    Then, logx = 33 log3     = 27 x 0.47712 = 12.88224    Since the characteristic in the resultant value of log x is 12   ∴The number of digits in x is (12 + 1) = 13    Hence the required number of digits in 333is 13.

Q: For x∈N, x>1,  and  p=logxx+1, q=logx+1x+2 then which one of the following is correct? 5293 2

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    p < q
    Correct
    Wrong
  • 2
    p = q
    Correct
    Wrong
  • 3
    p > q
    Correct
    Wrong
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    can't be determined
    Correct
    Wrong
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Answer : 3. "p > q"
Explanation :

Answer: C) p > q Explanation: kl>k+1l+1 for (k,l) > 0 and  k > l        Let     k = x+1    and   l = x       Therefore, x+1x>(x+1)+1(x)+1        (x + 1) > x       Therefore, log(x+1)log(x)>log(x+2)log(x+1)       ⇒logxx+1 >logx+1x+2

Q: The Value of  logtan10+logtan20+⋯⋯+logtan890 is 1016 1

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    -1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
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    1/2
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 2. "0"
Explanation :

Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450     = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1     ∵ tan(90-θ)=cotθ and tan 450=1     = log 1 + log 1 +.....+log 1    = 0.

Q: An industrial loom weaves 1.14 meters of cloth every second. Approximately, how much time will it take to weave 52 meters of cloth ? 2143 1

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    29.32 sec
    Correct
    Wrong
  • 2
    42.51 sec
    Correct
    Wrong
  • 3
    39.25 sec
    Correct
    Wrong
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    45.61 sec
    Correct
    Wrong
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Answer : 4. "45.61 sec"
Explanation :

Answer: D) 45.61 sec Explanation: Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in, 1.14 ----- 1 52.0 ------?  ⇒521.14= 45.61 sec

Q: If log 64 = 1.8061, then the value of log 16 will be (approx)? 3724 0

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    1.9048
    Correct
    Wrong
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    1.2040
    Correct
    Wrong
  • 3
    0.9840
    Correct
    Wrong
  • 4
    1.4521
    Correct
    Wrong
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Answer : 2. "1.2040"
Explanation :

Answer: B) 1.2040 Explanation: Given that, log 64 = 1.8061  i.e log43=1.8061  --> 3 log 4 = 1.8061 --> log 4 = 0.6020 --> 2 log 4 = 1.2040 ⇒log42=1.2040 Therefore, log 16 = 1.2040

Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 1603 1

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    1
    Correct
    Wrong
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    2
    Correct
    Wrong
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    4
    Correct
    Wrong
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    8
    Correct
    Wrong
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Answer : 2. "2"
Explanation :

Answer: B) 2 Explanation: Given a2 + b2 = c2   Now  1logc+ab  + 1logc-ab    = logbc+a + logbc-a   = logbc2-a2 = 2logbb = 2

Q: If log72 = m, then log4928 is equal to ? 1560 0

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    1/(1+2m)
    Correct
    Wrong
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    (1+2m)/2
    Correct
    Wrong
  • 3
    2m/(2m+1)
    Correct
    Wrong
  • 4
    (2m+1)/2m
    Correct
    Wrong
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Answer : 2. "(1+2m)/2"
Explanation :

Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4   = 12+122log72= 12+log72= 12 + m= 1+2m2.

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