Join ExamsbookAnswer : 3. "2/3"
Tickets are numbered from 1 to 18 are mixed up together and then 9 tickets are drawn at random. Find the probability that the ticket has a number, which is a multiple of 2 or 3.5
Q: Tickets are numbered from 1 to 18 are mixed up together and then 9 tickets are drawn at random. Find the probability that the ticket has a number, which is a multiple of 2 or 3.
- 11/3false
- 23/5false
- 32/3true
- 45/6false
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Answer : 3. "2/3"
Explanation :
Answer: C) 2/3 Explanation: S = { 1, 2, 3, 4, .....18 } => n(S) = 18 E1 = {2, 4, 6, 8, 10, 12, 14, 16, 18} => n(E1) = 9 E2 = {3, 6, 9, 12, 15, 18 } => n(E2) = 6 E3 =E1∩E2={6, 12, 18} => n(E3) = 3 ∴E=E1 ∪ E2 = E1+E2-E3 => n(E) = 9 + 6 - 3 =12 where E = { 2, 3, 4, 6, 8, 9, 10, 12, 12, 14, 15, 16, 18 } ∴P(E)=n(E)n(S)=1218=23
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